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To demonstrate the impact of order of operations using add, delete and/or move functions, we compared the difference of correction factors using different orders of operations to get the same locations of break points. Let us assume there are 4 break points (x1,x2,x3,x4) and the corresponding correction factors are f1,f2,f3,f4 and f5 respectively. The plot starts out as follows:

We wish to end up with a plot that looks as follows:

There are 3 ways we could achieve this, 1) by moving break point x2, 2) by adding a break point at the new position and then deleting break point x2, and 3) by deleting break point x2 and adding a new break point at the new position. These 3 options could result in different correction factors for the segments as can be seen as follows:

Option 1: Moving the break point

Before moving break point x2

Segment Id	Starting Point	Ending Point	Correction Factor
1	0	x1	f1
2	x1	x2	f2
3	x2	x3	f3
4	x3	x4	f4
5	x4	end	f5

After moving break point x2

Segment Id	Starting Point	Ending Point	Correction Factor
1	0	x1	f1
2	x1	new x2	f2
3	new x2	x3	f3
4	x3	x4	f4
5	x4	end	f5

Option 2: Adding the break point x5 and deleting the break point x2

Before doing any operations

Segment Id	Starting Point	Ending Point	Correction Factor
1	0	x1	f1
2	x1	x2	f2
3	x2	x3	f3
4	x3	x4	f4
5	x4	end	f5

After adding break point x5

Segment Id	Starting Point	Ending Point	Correction Factor
1	0	x1	f1
2	x1	x2	f2
3	x2	x5	f3
6	x5	x3	f3
4	x3	x4	f4
5	x4	end	f5

After deleting break point x2

Segment Id	Starting Point	Ending Point	Correction Factor
1	0	x1	f1
2	x1	x5	f2
6	x5	x3	f3
4	x3	x4	f4
5	x4	end	f5

Option 3: Deleting the break point x2 and adding the break point x5

Before doing any operations

Segment Id	Starting Point	Ending Point	Correction Factor
1	0	x1	f1
2	x1	x2	f2
3	x2	x3	f3
4	x3	x4	f4
5	x4	end	f5

After deleting break point x2

Segment Id	Starting Point	Ending Point	Correction Factor
1	0	x1	f1
2	x1	x3	f2
4	x3	x4	f4
5	x4	end	f5

After adding break point x5

Segment Id	Starting Point	Ending Point	Correction Factor
1	0	x1	f1
2	x1	x5	f2
6	x5	x3	f2
4	x3	x4	f4
5	x4	end	f5